All functions can be used in both the load script and in chart expressions. Asked 2 years, 9 months ago. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. however using the below sql statement im getting. The former produces a number representing the count of days between the two dates, while the latter produces an interval representation of the. 2188940092. Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. The following illustrates the syntax of the DATEPART. DATEADD () Adds or subtracts a specified time interval from a specified date. date_from, evnt. Improve this answer. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. (You can also subtract fractions of days, but that might be outside the scope of this answer. But your query is giving the last date of previous month. The DATEDIFF() function returns the number of days between two date values. - Find the “date_diff” in hours and multiply it by “60”. Then it subtracts a year if the birthdate hasn't passed. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. If you want an integer. Asked 1 year, 8 months ago. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. The result only contains the year, month and day, not the time. Second option is wrong when start hours/minutes/seconds is less then end. 1. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. 679 seconds. substr (to_char (to_date ('01-02-2018','mm-dd-yyyy'), <NLS_DATE_FORMAT>),4,3) The usual default value (for English-language versions of. NET SQL Added in; EF. Functions are based on a date-time serial number that equals the number of days since December 30, 1899. 999 would get rounded up to the next day anyway. it returns the difference in days if datepart is day. 2258064516 DATE_DIFF = 1. Admission_Date) > 5. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. Date manipulation is a common scenario when retrieving or storing data in a Microsoft SQL Server database. startdate: The first date or datetime value. 1. Select DATEDIFF (MM,0,GETDATE ()) Output - 1374, If getdate () output is "2014-07-23 19:33:46. We need to pad a zero for single-digit months. Firstly, for example, it doesn’t really hold a date, instead it records a datetime. 1. datediff isn't a function in Oracle. The days are in two different, adjacent months, so the answer is 1 month difference. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. MONTHS_BETWEEN returns number of months between dates date1 and date2. Another example using the. 7 Date and Time Functions. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. The format argument is a string format that specifies which unit the date should be rounded to. SELECT DATEDIFF (MONTH, '1/1/2014', '12/31/2014') and SELECT DATEDIFF (MONTH, '1/1/2014', '12/30/2014') both return 11. Share. 3. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. The Overflow Blog An intuitive introduction to text embeddings. Just to make the warning explicit to everyone looking at this answer: the subquery SELECT ROW_NUMBER() OVER ( ORDER BY c. 3. datediff() is not giving tHe result as I am working in Oracle. 3. This works, but it is a bit clumsy compared to the sql server function:So, the weird number you see is the difference between the two dates. For example, the function considers each of the following pairs of dates/timestamps to be exactly 1. Twinkles Twinkles. PostgreSQL. date_open are both of type date, you can simply subtract them to get a difference in days. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. . So far I have this: SELECT evnt. 0. The date argument is a DATE value (or an expression that resolves to a DATE value) that should be rounded. If date1 is earlier than date2 , then the result is negative. Returns 'Oracle Database 10g Enterprise Edition Release 10. DATEDIFF(interval, date1, date2) Parameter Values. datepart The units in which DATEDIFF reports the difference between the startdate and enddate. * 12 + (Extract(Month From CDate(EndDate)) - Extract(Month. Would give you rows where date2 (the later date) is 60 to 90 days later than date1. Returns a date string or the current date. We need to subtract a second from first day of current month. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Again, the expected results would be a value of 1. Here is an example that uses date functions. declare @EmployeeStartDate datetime='01-Sep-2013' declare @EmployeeEndDate datetime='15-Nov-2013' select DateDiff (mm,@EmployeeStartDate, DateAdd (mm, 1,@EmployeeEndDate)) If. If date1 is earlier than date2 , then the result is negative. SS: 差異を秒数で計算します。. SQR for PeopleSoft provides an extensive set of date edit masks. %DateAdd . MONTHS_BETWEEN (TO_DATE ('2003/01/01', 'yyyy/mm/dd'), TO_DATE ('2003/03/14', 'yyyy/mm/dd') ) would return -2. If the resulting date would have more days than are available in the resulting month, the result is the last day of that month. columns. Current Date/Time. Delaying Execution. I have tried it before. ADD_MONTHS. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. Functions. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. Unfortunately, Oracle SQL doesn't allow the DATEDIFF function. 5 days to a given date. We’re calculating months of service in this example. g. Syntax:DATEDIFF Examples Using All Options. 2425. Example: DATEADD(MONTH, 1, DATE '2001-01-31') DATEDIFF { DATEDIFF |. Share. The NEXT_DAY() function accepts two arguments:. 1. Oracle SQL Hours Difference between dates in HH:MM:SS. 997 All results I use in BETWEEN operator, therefore last 'day' should include last millisecond of the very day. I guess I did not read the question in depth. Aug 17, 2021 at 11:13. oracle; datediff; or ask your own question. As Spark doesn't provide the other unit, I use below method, select (bigint (to_timestamp (endDate))) - (bigint (to_timestamp (startDate))) as time_diff. MONTH, YEAR, WEEK, etc are not allowed for. That prevents. ORA-00937 when calculating a sub-value in an aggregate select statement. The following shows the syntax of the syntax of the NEXT_DAY() function:. Tdy. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. This is going to be short:. For example, suppose you have values below the start and end times. Each Standard calendar week is defined to start on Sunday and it spans 7 days. Share. Sorted by: 193. If date1 and date2 are either the same days of the month or both last days of months, then the result is always an integer. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate Result: DiffDate 61 So, for example: WHERE date2 - date1 BETWEEN 60 AND 90. Oracle Fusion Application Toolkit Cloud Service - Version 11. 40 hours. Then, we need a 2-digit month string. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. . For many values of the local settings, this would simply fail. The dateadd function adds or subtracts a number of specified time units from a given date. The datediff function can return the difference between two dates in days, months, years, minutes, etc. Weeks. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. The MDX DateDiff function for Essbase returns the difference (a number) between two input dates in terms of the specified date-parts, following a standard Gregorian calendar. A number representing the input date between January 1, 1970 and Dec 31, 2037. That prevents. Type. Example. Parameter Description; date1, date2: Required. For example, assume that you had two elements, FIRST_NAME and LAST_NAME to concatenate into a 30-character field. 1. SQL is a standard language for storing, manipulating and retrieving data in databases. #. There are two methods to achieve this. g. Try SELECT SYSTIMESTAMP + INTERVAL '5' MINUTE, SYSTIMESTAMP + 5 / 24 / 60 to convince yourself. Syntax %DateAdd(date_from, add_days) Description. For example, adding three months or 12 days to a starting date. Currently, my code just returns zero on the right side of the decimal place. 取得一季中的第一天：. SS: 差異を秒数で計算します。. The following table lists all the valid datepart values. VALID_FROM_DTTM between DATEADD(m,-1,DATEADD(m, DATEDIFF(m,0,GETDATE()),0)) and. subtract and give the difference in number of. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. Date ) AS NextDate FROM. (date1 - date2)The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. COMPUTE days3 = CTIME. Once you have the date difference, you can use simple techniques to express the difference in days, hours, minutes or seconds. user637544 Jun 1 2009 — edited Jun 1 2009. 997 to avoid that. 01/31/2021: Introduced in SQL Server 2012. DAYS(date2 - date1). The next example will show the differences between two dates for each specific datapart and abbreviation. current_time() returns the date and time on the database client side. SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. g. You could, of course, write your own function and call that. Oracle doesn't have a DATEDIFF() function. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). 0- 64bit Production With the Partitioning and Data Mining options'. Date 1: 10th March 2011. 00. The part can be the day of the date, month of the date, year of the date etc. CASE WHEN a. 1. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Oracle offers its own solution, although does not have the DATEDIFF function. enddate, e3. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. I have to get the date from the system and calculate the date difference in days. February 28 and March 31), the fractional portion is zero, even if the days of the month are not the same. {"payload":{"allShortcutsEnabled":false,"fileTree":{"inst/csv":{"items":[{"name":"jarChecksum. The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. DATE_FROM_UNIX_DATE. (date1 - date2)9 Answers. for oracle: months_between. CODE = 'CONTACT_CLIENT' THEN a. The functions in this section use a format string that is compatible with JodaTime’s DateTimeFormat pattern format. This function is not sensitive to the NLS_CALENDAR session parameter. SELECT TIMESTAMP_FORMAT (“2021-03-15”, “%Y”) as “Year of the date”; TO_DATE. Select between two months. I am trying to use the INTNX function to get the first and last days of the previous month. Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. columns c puts a limit on how many dates are returned. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. The DATEDIFF function does not calculate the difference in months based on days. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. Given two dates then the difference between them is a number of full calendar months and the remainder is the number of days (and hours, minutes and seconds) - this is easy to find using the MONTHS_BETWEEN function and some modulo arithmetic (see my. There are two methods to achieve this. DATE_ADD () Add time values (intervals) to a date value. This formula subtracts the first day of the ending month (5/1/2016) from the original end date in cell E17 (5/6/2016). e. This works because you have no issue with months and years or one-digit vs. Constructs a DATE value. The table contains the data about each staff member’s employment date. 10 Answers. Follow answered Aug 3, 2011 at 18:51. The DATEDIFF function will return the difference count between two DateTime periods with an integer value whereas the DATEDIFF_BIG function will return its output in a big integer value. 1. from this previous question How to calculate age in T-SQL with years, months, and days you can do procedure like this. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. So given Netezza is based on PostgreSQL, so it's AGE function, is equivalent to Snowflake's DATEDIFF, but like PostgreSQL interval it defaults to expressing it in simplified terms of Years/Months/Days. Also the order of the parameters is swapped. 005479 (1 year + 2/365 years). 1 Answer. Fractions are allowed; you can add 2. Take these examples: Example 1 Date 1: 10th March 2011 Date 2: 3rd Feb 2011 MONTHS_BETWEEN = 1. ) and the. 2. select distinct e1. If date1 is earlier than date2, then the result is negative. S is milliseconds in one or up. 4193548 The number of whole months can be split into. Share. select S. )CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;If this solve your problem, here's the sql server syntax, just replace the variable @yourDate with your column name. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. Discussion: To calculate the difference between the timestamps in Oracle, simply subtract the start timestamp from the end timestamp (here: arrival - departure ). The table contains the data about each staff member’s. In this tutorial, you have learned how to use the Oracle INTERVAL data type to store periods of time in the tables. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. The function INTCK ('MONTH','31jan1991'd,'1feb1991’d) returns 1, because the two dates lie in different months that are one month apart. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. Oracle equivalent to SQL Server/Sybase DateDiff. I usually used MySQL or sometimes Oracle but now I have to switch to Teradata. I have a question though. Converting Valid Character Strings to Dates, Times, or Timestamps. The result is formatted according to the Format parameter. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. The following example illustrates how to use the. DATE_SUB () Subtract a time value (interval) from a date. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. To retrieve this number, use any of the following functions: Today (), TodateEx (), GetFirstDate (), GetLastDate (), DateRoll (). NEXT_MONTH: Returns the first day of the next month after the specified date. SELECT DATEDIFF (month, '2017/08/25', '2011/08/25') AS DateDiff; Edit the SQL Statement, and click "Run SQL" to see the result. 在本文中，我们介绍了oracle数据库中的datediff函数。通过指定日期部分、开始日期和结束日期，我们可以使用datediff函数计算两个日期之间的差异。这对于计算日期之间的天数、小时数、分钟数等非常有用。希望本文对您理解datediff函数的使用有所帮助。 MySQL DATEDIFF: Calculating weeks, months, or years between two dates. DECLARE @date datetime2 = '2021-01-07 14:36:17. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. 3. E. SQL date formatfunctions in SQL server are really powerful and really helps to deliver impactful data analytics and reports. However, i think for Oracle (not sure of the latest versions) there is no DATEDIFF(), but rather Oracle allows you to simply subtract one date from another. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. For example, you can use this function to find the date that is 7000 minutes from today: number = 7000, datepart = minute, date = today. Must be one of the values listed in Supported Date and Time Parts (e. g. The second method uses an extract function to obtain the years, months, and days separately. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. hh is a two digits of hour (00 through 23). We learned with examples, how to get information. PRINT DATEDIFF(Day, 2010-01-20, 2010-01-01) RETURN 19 Which is correct. DATEADD (date part, units, date or datetime) Return date math results: datetime DATEDIFF (date part, start date, end date) Give the difference between 2 dates in units specified by. TIMESTAMP or TIMESTAMPZ. The starting day of the week used by the format models DAY, DY, and D is specified. It should have been DATEDIFF NOT DATEADD with respect to the WEEK parameter. You cannot mix xdofx statements with XSL expressions in the same context. to get the date one second before midnight of. Calculates the difference in week numbers and year numbers, subtracts the week numbers and then multiplies the result by 2 to calculate number of non-workdays between the two dates. (Query using SQL server 2005 and 2008 is allowed). . MONTHS_BETWEEN = 1. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Viewed 32k times. 8. You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365. So I am porting many SQL Procedures to Oracle. Any help would be appreciated. 032258Currently, my code just returns zero on the right side of the decimal place. Improve this answer. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. ss is two digits of second (00 through 59). Result: 505 rows listed. date_from) = 1. So you just have to multiply to get the result in minutes instead: SELECT (date2 - date1) * 24 * 60 AS minutesBetween FROM. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. I am running a simple DATEDIFF query but it doesn't seem to calculate the days properly or i'm doing something wrong. . I can mention four important functions of MS SQL Server that can be very useful: 1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):. 000 which is the start of the. ops$tkyte@8i> select months_between ( end_date, start_date ), 2 trunc ( months_between ( end_date, start_date ) /12 ) Years, 3 mod (. Date3(year, month, day) – similar to the ‘Date’ function described above, except that the three parameters are passed in as separate year, month and day values. For example, we can use the DATEPART function to get the day of a given date to determine whether an order was placed on Sunday or not. . ReturnDate)) + ' days') ELSE CAST(DATEDIFF(day, Trips. 208333, so the value is correct! So now that we know how subtracting dates. txt","contentType":"file"},{"name. 3. Table 9. I am trying to come up with a way in Oracle to calculate the difference between dates in days. This gets the year difference between the birth date and the current date. What I am using is (Today-Dob)/30/12, but this is not accurate as some months have 31 days. %DateDiff – returns the number of days between two date values. Oracle 9i and later versions support CURRENT_DATE and CURRENT_TIMESTAMP. , for the Oracle database: sale_date >= TRUNC (sysdate) AND sale_date < TRUNC (sysdate + INTERVAL '1' DAY) Another common obfuscation is to compare dates as strings as shown in the following PostgreSQL example:The trick here is to get the first day of the next month which will always be 01-NextMonth-Year. – user330315. DP_MONTH returns the distance between the months capturing the input dates. This function helps to retrieve any particular value of the timestamp in any format that we wish. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. 1 Answer. Improve this answer. The add_days variable can be negative. FROM_DAYS(): This function finds the date from the specified numeric date value. DATEDIFF is wrong. Join our newsletter and get access to exclusive content every month. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . Also I am not sure about Oracle, mysql,. Function. Next to calculate a month of services in a company by a user we would use ‘m’ to calculate the difference value. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. Snowflake doesn't offer a function that does that. 2323 days) multiply by 24 = hours, another 60 = minutes, another 60 = seconds. Calculates the difference in days between the two dates. Oracle's database does not have (nor need) a datediff() function. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. date_to, DATEDIFF(DD, evnt. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. Then it would also be helpful to be able to. CREATE TABLE [table] ( ID int IDENTITY(1,1) PRIMARY KEY, Title nvarchar(20), Date date, Amount money. DATE_SUB () Subtract a time value (interval) from a date. The following query selects all rows with a date_col value from within the last 30 days: . ie if the month when the query is run is march 2013. Multiply it by seven to give the number of weeks spanned. 000000 1. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. DateAdd. Enter a date format string that describes the Date2 parameter. SELECT --Start with total number of days including weekends (DATEDIFF (dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend (DATEDIFF (wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1 ELSE 0 END) --If EndDate is a Saturday, Subtract 1 FROM dual. If date1 is later than date2 , then the result is positive. 1. YEAR: Stores the year information only, either in 2-digit or 4-digit format. Goal. This question is asked many times and one of the suggested queries to get months between 2 dates is not working. The syntax for these extended functions is. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. We are now using NHibernate to connect to different database base on where our software is installed. You may have to re-cast to a DATE datatype first. The Oracle NEXT_DAY() function returns the date of the first weekday specified by day name that is later than a date. Move the start date to the next Monday, then add the calculated weeks. Follow edited Oct 19, 2016 at 9:44. Concatenates a date to a time on either side of the + symbol and returns a TIMESTAMP or TIMESTAMPTZ. select datediff (q,'03-30-2005','04-01-2005') will return 1. As we can see in the screen shot the query displays the months between the two dates. 2. I want to select some data from one table if a date from another table is at least 6 months before today. 可以用以下方法在oracle中实现该函数的功能: 1. declare @datetime datetime; set @datetime = getdate (); select @datetime; select dateadd (year,datediff (year,0,@datetime),0); select dateadd (month,datediff (month,0,@datetime),0); select dateadd (day,datediff. Returns. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. If I run. Get the number of months between two dates. Specifically, it gets the difference between 2 dates with the results returned in date units specified as years, months days, minutes, seconds as a bigint value. DATEDIFF accepts either. If date1 and date2 are either the same days of the month or both last days of months, then the. txt","path":"inst/csv/jarChecksum. SQL DATEPART. You can use this methodology to determine the first day of 3 months ago, and the last day of the previous month: select DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ())-3, 0) --First day of 3 months ago select DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) --Last Day of previous month. Join our newsletter and get access to exclusive content every month. The days are in two different, adjacent months, so the answer is 1 month difference. 0 for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query . The math is 100% accurate for dates within a couple of hundred years or so. Add 18 years to the date in the BirthDate column, then return the date: SELECT LastName, BirthDate, DATEADD (year, 18, BirthDate) AS DateAdd FROM Employees; Try it Yourself ». Asked 10 years, 2 months ago. StartDate,. The application passes in two parameters: a string representing the number of the desired month (i. DATEENTERED ,* from sometable S where S. DateDiff(“m”, Fields! starting date. The default is date format 1.